The crystal field splitting energy is:

1.	The heat of formation between the two levels (e and t2) in tetrahedral splitting
2.	The total pairing energy of the two levels (e and t2) in tetrahedral splitting.
3.	The sum of the energy levels in an octahedral crystal field splitting.
4.	The combined energy of the two levels (eg and t2g) in octahedral splitting.

[Cr(NH₃)₆]³⁺ is paramagnetic ,while ${\left[\mathrm{Ni}{\left(\mathrm{CN}\right)}_4\right]}^{2-}$ is diamagnetic because:

A solution of [Ni(H₂O)₆]²⁺ is green, but a solution of [Ni(CN)₄]^2– is colorless because:

[Fe(CN)₆]^4– and [Fe(H₂O)₆]²⁺ are of different colors in dilute solutions because :

The nature of bonding in metal carbonyls is -

The greater value of the stability constant of complex salt indicates:

1. The greater proportion of products.

2. The greater proportion of reactants

3. Lesser concentration of catalyst at equilibrium

4. All of the above

The correct order for the wavelengths of absorption in the visible region for the following is:
\(\left[\mathrm{Ni}\left(\mathrm{NO}_2\right)_6\right]^{4-},\left[\mathrm{Ni}\left(\mathrm{NH}_3\right)_6\right]^{2+},\left[\mathrm{Ni}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}\)
1. $[\mathrm{Ni}{\left({\mathrm{H}}_2\mathrm{O}\right)}_6{]}^{2+}$ < $[\mathrm{Ni}{\left({\mathrm{NH}}_3\right)}_6{]}^{2+}$ < $[\mathrm{Ni}{\left({\mathrm{NO}}_2\right)}_6{]}^{4-}$

2. $[\mathrm{Ni}{\left({\mathrm{H}}_2\mathrm{O}\right)}_6{]}^{2+}$ > $[\mathrm{Ni}{\left({\mathrm{NH}}_3\right)}_6{]}^{2+}$ > $[\mathrm{Ni}{\left({\mathrm{NO}}_2\right)}_6{]}^{4-}$

3. $[\mathrm{Ni}{\left({\mathrm{NH}}_3\right)}_6{]}^{2+}$ > $[\mathrm{Ni}{\left({\mathrm{H}}_2\mathrm{O}\right)}_6{]}^{2+}$> $[\mathrm{Ni}{\left({\mathrm{NO}}_2\right)}_6{]}^{4-}$

4.  $[\mathrm{Ni}{\left({\mathrm{H}}_2\mathrm{O}\right)}_6{]}^{2+}$ > ${\left[\mathrm{Ni}{\left({\mathrm{NO}}_2\right)}_6\right]}^{4-}$> [Ni(NH₃)₆]²⁺

The number of unpaired electrons in the following complexes respectively are-

${\mathrm{K}}_4\left[\mathrm{Mn}{\left(\mathrm{CN}\right)}_6\right],<mspace\; width="1em"></mspace>\mathrm{Fe}{\left({\mathrm{H}}_2\mathrm{O}\right)}_6{]}^{2+},<mspace\; width="1em"></mspace>{\mathrm{K}}_2\left[{\mathrm{MnCl}}_4\right]$

1. 1, 4, 5

2. 2, 4, 5

3. 0, 3, 4

4. 2, 3, 4

Match Column-I with Column-II and mark the correct option.

Codes:
1. i=d, ii=c, iii=b, iv=a

2. i=c, ii=d, iii=b, iv=a

3. i=c, ii=d, iii=a, iv=b

4. i=a, ii=c, iii=b, iv=d