Q. No.
When a photon with a wavelength of 150 pm strikes an atom, one of its inner bound electrons is ejected at a velocity of 1.5 × 107 m s–1 . The energy with which it is bound to the nucleus would be:
1. 32.22 × 10–16 J
2. 12.22 × 10–16 J
3. 22.27 × 10–16 J
4. 31.22 × 10–16 J
The wavelength for the emission transition, the series to which this transition belongs and the region of the spectrum if it starts from the orbit having a radius of 1.3225 nm and ends at 211.6 pm would be respectively -
1) The transition is from the 5th orbit to the 2nd orbit. It belongs to the Balmer series. wavenumber for the transition is 800 nm
2) The transition is from the 4th orbit to the 2nd orbit. It belongs to the Balmer series. wavenumber for the transition is 634 nm
3) The transition is from the 5th orbit to the 2nd orbit. It belongs to the Balmer series. wavenumber for the transition is 434 nm
4) The transition is from the 6th orbit to the 2nd orbit. It belongs to the Balmer series. wavenumber for the transition is 534 nm
If the position of the electron were measured with an accuracy of +0.002 nm, the uncertainty in the momentum of the electron would be:
1. 5.637 × 10–23 kg m s–1
2. 4.637 × 10–23 kg m s–1
3. 2.637 × 10–23 kg m s–1
4. 3.637 × 10–23 kg m s–1
The quantum numbers of six electrons are given below. Arrange them in order of increasing energies.
1. n = 4, l = 2, ml = –2 , ms = –1/2
2. n = 3, l = 2, ml = 1 , ms = +1/2
3. n = 4, l = 1, ml = 0 , ms = +1/2
4. n = 3, l = 2, ml = –2 , ms = –1/2
5. n = 3, l = 1, ml = –1 , ms = +1/2
6. n = 4, l = 1, ml = 0 , ms = +1/2
1) 5(3p) < 2(3d) < 6(4p) < 1 (4d) = 4(3d) < 3(4p)
2) 5(3p) < 2(3d) = 4(3d) < 3(4p) = 6(4p) < 1 (4d)
3) 6(4p) < 1 (4d) < 5(3p) < 2(3d) < 4(3d) < 3(4p)
4) 5(3p) < 2(3d) < 4(3d) < 3(4p) < 6(4p) < 1 (4d)
1. 2p and 3p
2. 4p
3. 2p
Among the following pairs of orbitals the orbital that will experience the larger effective nuclear charge respectively is -
(i) 2s and 3s, (ii) 4d and 4f, (iii) 3d and 3p.
1. 2s, 4d, 3p
2. 3s, 4f, 3d
3. 3s, 4f, 3p
4. 2s, 4d, 3d
The unpaired electrons in Al and Si are present in the 3p orbital. The electrons that will experience a more effective nuclear charge from the nucleus are :
1. Electrons in the 3p orbital of silicon
2. Electrons in the 5d orbital of aluminium
3. Electrons in the 3p orbital of aluminium
4. Electrons in the 5p orbital of silicon
Identify the element with the highest number of unpaired electrons in its ground state from the given options :
| 1. | P
|
2. | Fe
|
| 3. | Kr
|
4. | Cr |
The number of electrons that can be present in the subshells having ms value of \(-\frac{1}{2}\) for n = 4 are:
| 1. | 36 | 2. | 4 |
| 3. | 16 | 4. | 2 |
The atomic number of elements whose outermost electronic configuration are represented by 3s1 and 2p5 respectively, is:
| 1. | 9, 7 | 2. | 9, 11 |
| 3. | 11, 5 | 4. | 11, 9 |
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