The period in the modern periodic table indicates the value of :
1. Atomic number
2. Atomic mass
3. Principal quantum number
4. Azimuthal quantum number.
The number of orbitals indicated by the following set of quantum numbers, n = 3, l = 2, m =+2 is:
1. 1
2. 2
3. 3
4. 4
The maximum number of neutrons are present in the nuclei of:
1. \(_8^{16}\mathrm{O}\)
2. \(_{12}^{24}\mathrm{Mg}\)
3.\(_{26}^{56}\mathrm{Fe}\)
4. \(_{38}^{88}\mathrm{Sr}\)
The complete symbol for the atom with the given atomic number (Z) and atomic mass (A) would be, respectively :
| i. | Z = 17 , A = 35. |
| ii. | Z = 92 , A = 233. |
| iii. | Z = 4 , A = 9. |
1.
2.
3.
4.
Yellow light emitted from a sodium lamp has a wavelength (λ) of 580 nm. The frequency (ν) and wave number of this yellow light would be, respectively:
1. 517 × 1014 s–1 , 172 × 106 m–1
2. 6.17 × 1014 s–1 , 1.72 × 106 m–1
3. 4.17 × 1014 s–1 , 2.72 × 106 m–1
4. 5.17 × 1014 s–1 , 1.72 × 106 m–1
The energy of the photon with a frequency of 3 × 1015 Hz is:
1. 1.988 × J
2. 1.588 × J
3. 1.288 × J
4. 2.988 × J
A photon of wavelength 4 × 10–7 m strikes a metal surface, the work function of the metal being 2.13 eV. The kinetic energy of emission would be:
| 1. | 0.97 eV | 2. | 97 eV |
| 3. | 4.97 × eV | 4. | 5.84 × 105 eV |
Which of the following statements correctly compares the energy required to ionize a hydrogen atom when its electron is in the 5th orbit (n = 5) with the ionization energy from the ground state (n = 1)?
| 1. | More energy is required to ionize an electron in the 5th orbital of a hydrogen atom as compared to that in the ground state
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| 2. | More energy is required to ionize an electron in the 8th orbital of a hydrogen atom as compared to that in the ground state
|
| 3. | Less energy is required to ionize an electron in the 5th orbital of a hydrogen atom as compared to that in the ground state
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| 4. | Less energy is required to ionize a neutron in the 6th orbital of a hydrogen atom as compared to that in the ground state |
The possible values of n, l, and m for the electron present in 3d would be respectively:
1. n = 3, l = 1, m = – 2, – 1, 3, 1, 2
2. n = 3, l = 3, m = – 2, – 1, 0, 1, 2
3. n = 3, l = 2, m = – 2, – 1, 0, 1, 2
4. n = 5, l = 2, m = – 2, – 1, 0, 1, 2