Loss in energy in the transformer is due to 

1.  Hysteresis

2.  Eddy current loss

3.  Leakage of flux

4.  All of these

An alternatingcurrentisgivenas \(i = i_1 \cos\omega t+i_2\sin\omega t\). The RMS current is given by;
1. \(\dfrac{i_1+i_2}{\sqrt{2}}\)
2. \(\dfrac{(i_1+i_2)^2}{\sqrt{2}}\)
3. \(\sqrt{\dfrac{i_1^2+i^2_2}{2}}\)
4. \(\dfrac{\sqrt{i_1^2+i^2_2}}{2}\)

In a step-up transformer, the turn ratio is 1:2. A Leclanche cell (e.m.f. 1.5V) is connected across the primary coil. The voltage developed in the secondary coil would be-

1. 3.0 V

2. 0.75 V

3. 1.5 V

4. Zero

A \(220~\text{V}, 50~\text{Hz}\) AC source is connected to an inductance of \(0.2~\text{H}\) and a resistance of \(20~\Omega\) in series. What is the current in the circuit:
1. \(10~\text{A}\)
2. \(5~\text{A}\)
3. \(33.3~\text{A}\)
4. \(3.33~\text{A}\)

Two coils have a mutual inductance of 5 mH. Current changes in the first coil according to the equation I = $I_0$cos wt, where $I_0$ = 10 A and $\mathrm{\omega }<mspace\; width="1em"></mspace>=<mspace\; width="1em"></mspace>100\mathrm{\pi }$ rad/s. Maximum value of e.m.f. induced in the second coil is

1.  5$\pi$ volt

2.   2$\pi$ volt

3.  4$\pi$ volt

4.  $\pi$ volt

The ratio of the number of turns in secondary to primary in an ideal transformer varies from 50 to 550. If the power input is P, then its output power is  -

1.  11P

2.  $\frac{\mathrm{P}}{11}$

3.  $\frac{18P}{111}$

4.  P

In a LCR series network, ${\mathrm{V}}_{\mathrm{L}}=40<mspace\; width="1em"></mspace>\mathrm{V},<mspace\; width="1em"></mspace>{\mathrm{V}}_{\mathrm{C}}=20<mspace\; width="1em"></mspace>\mathrm{V}<mspace\; width="1em"></mspace>\mathrm{and}<mspace\; width="1em"></mspace>{\mathrm{V}}_{\mathrm{R}}=15<mspace\; width="1em"></mspace>\mathrm{V}$. The supply voltage is

1.  25V

2.  75V

3.  35V

4.  Zero

In a LCR circuit having L = 8.0 henry, C = 0.5 $\mathrm{\mu F}$ and R = 100 $\mathrm{\Omega }$ in series, the resonance frequency (in Hz) is 

1.  $\frac{250}{\mathrm{\pi }}\mathrm{Hz}<mspace\; width="1em"></mspace><mspace\; width="1em"></mspace>$

2.  $\frac{600}{\mathrm{\pi }}\mathrm{Hz}<mspace\; width="1em"></mspace><mspace\; width="1em"></mspace>$

3.  $\frac{500}{\mathrm{\pi }}\mathrm{Hz}<mspace\; width="1em"></mspace>$

4.  $500<mspace\; width="1em"></mspace>\mathrm{Hz}$

At resonance, the value of the power factor of the circuit is -

1.  1

2.  Zero

3.  Between zero and 1

4.  More than 1

A step-down transformer is employed to reduce the main supply of AC from \(220~\text{V}\) to \(11~\text{V}\). If the primary coil draws a current of \(5~\text{A}\) and the secondary supplies a current of \(90~\text{A}\), then the efficiency of the transformer is:
1. \(10\%\)
2. \(95\%\)
3. \(90\%\)
4. \(80\%\)