1 M, 2.5 litre NaOH solution is mixed with another 0.5 M and 3 litre NaOH solution.
The molarity of the resultant solution is:

1. 0.80 M 2. 1.0 M
3. 0.73 M 4. 0.50 M

Subtopic:  Concentration Based Problem |
 76%
From NCERT
AIPMT - 2002
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Which among the following has the maximum number of molecules?

1. 7 gm N2

2. 2 gm H2

3. 16 gm NO2

4. 16 gm O2

Subtopic:  Moles, Atoms & Electrons |
 87%
From NCERT
AIPMT - 2002
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The percentages of C, H, and N in an organic compound are 40%, 13.3%, and 46.7% respectively.
The empirical formula of the compound is:

1. C3H13N3 2. CH2N
3. CH4N 4. CH6N
Subtopic:  Empirical & Molecular Formula |
 74%
From NCERT
AIPMT - 2002
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Find the molarity of liquid HCl if the density of liquid HCl is 1.17 g/cc.

1. 36.5 2. 18.25
3. 32.05 4. 42.10
Subtopic:  Concentration Based Problem |
 68%
From NCERT
AIPMT - 2001
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Molecular mass of  (i) H2O (ii) CO2 (iii) CH4 are respectively:

1. 18u,16u ,44u

2. 18u,44 u,16u

3. 16u,18u,44u

4. 44u,16u,18u

Subtopic:  Introduction |
 89%
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In sodium sulphate (Na2SO4), the mass percent of sodium, sulfur and oxygen is:

1. 32.4%, 45.05%, 22.6%

2. 22.6%, 45.05%, 32.4%

3. 32.4%, 22.6%, 45.05%

4. 45.05%, 32.4%, 22.6%

Subtopic:  Introduction |
 77%
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The amount of CO2 that can be produced when 2 moles of carbon are burnt in 16 g of dioxygen is:
1. 22 g
2. 44 g
3. 0.5 g
4. 11 g

Subtopic:  Limiting Reagent | Equation Based Problem |
 71%
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The amount of copper (in grams) that can be obtained from 100 g of copper sulphate (CuSO4is:

1. 54.00 2. 39.81
3. 63.50 4. 159.50
Subtopic:  Moles, Atoms & Electrons |
 71%
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In an iron oxide, the mass percent of iron and oxygen are 69.9 and 30.1, respectively. The empirical formula of the oxide of iron will be:

1. Fe3O2

2. Fe2O2

3. Fe2O3

4. Fe3O4

Subtopic:  Empirical & Molecular Formula |
 71%
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The average atomic mass of chlorine using the following data would be:

Isotope

% Natural

Abundance

Molar

Mass

35Cl  75.77 34.9689
37Cl  24.23 36.9659

1. 38.4527 u

2. 37.4527 u

3. 36.4527 u

4. 35.4527 u

Subtopic:  Empirical & Molecular Formula |
 78%
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