The –OH group of an alcohol or the carboxylic acid can be replaced by – Cl using: 

1.	Hypochlorous acid	2.	Chlorine
3.	Hydrochloric acid	4.	Phosphorous pentachloride

Chloropicrin is obtained by the reaction of: 

1. Nitric acid on chlorobenzene.

2. Chlorine on picric acid.

3. Nitric acid on chloroform.

4. Steam on carbon tetrachloride.

Given below is a reaction sequence:
\(\begin{aligned} & CH_3CH_2Cl\xrightarrow{NaCN}X\xrightarrow{H_2/Ni}Y\\ &Y\xrightarrow{\text{Acetic Anhydride}}Z \end{aligned}\)

Z in the above reaction is:

1. CH₃CH₂CH₂NHCOCH₃

2. CH₃CH₂CH₂NH₂

3. CH₃CH₂CH₂CONHCH₃

4. CH₃CH₂CH₂CONHCOCH₃

 \(CH_3CH_2CHCl_2\) upon reaction with \(NaNH_2\)gives:

1.		2.
3.		4.

obtained by chlorination of n-butane, will be:
1.  Meso form
2.  Racemic mixture
3.  d-form
4.  l-form

An organic compound A$\left(C_4{H}_{9}Cl\right)$ in reaction with Na/diethyl ether gives a hydrocarbon which on monochlorination gives only one chloro derivative. A is:

1. t-butyl chloride
2. sec. butyl chloride
3. Iso butyl chloride
4. n-butyl chloride

Wurtz reaction is not preferred for the preparation of alkanes containing an odd number of carbon atoms because:

A hydrocarbon C₅H₁₀ does not react with chlorine in the dark but gives a single monochloro compound C₅H₉Cl in bright sunlight. Hydrocarbon could be:

The above-mentioned compounds that react faster in S N₂ reaction with OH^- from each given pair respectively are:
1. CH₃Br, CH₃I
2. CH₃Br, (CH₃)₃CCl
3. CH₃I, CH₃Cl
4. CH₃I, (CH₃)₃CCl

Out of ${\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{CH}}_2\mathrm{Cl}$ $\mathrm{and}$ ${\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{CHClC}}_6{\mathrm{H}}_5$, the one that gets easily hydrolyzed by aqueous KOH is :

1. ${\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{CHClC}}_6{\mathrm{H}}_5$ 

2. ${\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{CH}}_2\mathrm{Cl}$

3. Both react equally

4. None of the above