What is incorrect for Hemophilia?

1. In this disease, a single protein that is a part of the cascade of proteins involved in the clotting of blood is affected.

2. In an affected indlvidual a simple cut will result in non-stop bleeding.

3. The heterozygous female (carrier) for haemophilia may transmit the disease to sons.

4. The possibility of a female becoming a haemophilic is extremely rare because mother of such a female has to be hemophilic and the father should be a carrier.

Subtopic:  Mendelian Disorders: Hemophilia |
 70%
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Sickle cell anaemia results from.

1. A chromosomal aberration

2. Non disjunction of autosome

3. A point mutation

4. Blood transfusion reaction

Subtopic:  Mendelian Disorders: Sickle Cell Anemia |
 79%
From NCERT
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What is the mode of inheritance of phenylketonuria?

1. Autosomal recessive

2. Autosomal dominant

3. Sex linked recessive

4. Sex linked dominant

Subtopic:  Mendelian Disorders |
 79%
From NCERT
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Failure of cytokinesis after telophase stage of cell divislon results in an increase in a whole set of chromosomes in an organism and, this phenomenon is known as:

1. Aneuploidy

2. Translocation

3. Polyploidy.

4. Inversion

Subtopic:  Non - Disjunction & Aneuploidy |
 75%
From NCERT
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Which of the following is not a feature of Down's Syndrome?

1. It is caused by a non-disjunction in an autosome

2. The affected individual has trisomy of chromosome 21

3. The aflected individual has a characteristic simian palmar crease

4. The mental development of affected individual is normal

Subtopic:  Non - Disjunction & Aneuploidy |
 71%
From NCERT
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Identify the incorrect statement:

(1) In addition to recombination, mutation is another phenomeonon that leads to variation in DNA.

(2) Chromosomal aberrations are commonly observed in cancer cells.

(3) A classical example of a point mutation is sickle cell anaemia.

(4) Non ionising radiations cannot be mutations. 

Subtopic:  Mendelian Disorders: Sickle Cell Anemia |
 77%
From NCERT
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Pedigree analysis is resorted to for genetic analysis in humans rather than conventional genetic methods because:

I. Choice matings are not possible

II. Number of progeny is limited

Of the two statements:

(1) Only I is correct

(2) Only II is correct

(3) Both I and II are correct

(4) Both I and II are incorrect

Subtopic:  Pedigree Analysis: Basics |
 53%
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Match each item in Column I with one item in Column II and chose your answer from the codes given below:

Column I

Disorder

Column II

Feature

I. Phenylketonuria

II. Sickle Cell anemia

III. Down's Syndrome

IV. Turner's Syndrome

(i) Rudimentary ovaries

(ii) Gynecomastia

(iii) Trisomy 21

(iv) Lack of enzyme PAH

(v) Lack of tyrosinase

(vi) Mutation GAG to GUG

(vii) Mutation GUG to GAG

 

1. I - v; II - vii; III - iii; IV - i

2. I - iv; II - vi; III - iii; IV - i

3. I - v; II - vi; III - iii; IV - ii

4. I - v; II - vi; III - iii; IV - i

Subtopic:  Mendelian Disorders |
 59%
From NCERT
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In a monohybrid cross F1 progeny resemble neither of the parents. What would be true in this case?

1. The parental traits would not appear in any of the F2 -progenies

2. The F2 phenotypic ratio will be different from the F2 genotypic ratio

3. It could be a case of incomplete dominance

4. The F2 phenotypic ratio will be similar to any Mendelian monohybrid cross

Subtopic:  Monohybrid Cross: 1 |
 76%
From NCERT
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The two alleles of a gene pair are located on:

1. Homologous sites on homologous chromosomes

2. Heterologous sites on homologous chromosomes

3. Homologous sites on heterologous chromosomes

4. Heterologous sites on heretologous chromosomes

Subtopic:  Chromosomal Basis of Inheritance: Further Considerations |
 75%
From NCERT
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