D is N-methyl aniline in the given below sequence of reaction:
\(\text A\xrightarrow{\bf\text{ reduction }}\text B\xrightarrow{\bf\text {CHCl}_3\text{/KOH}}\text C\xrightarrow{\bf\text{ reduction }}\text D\)
Structure of A can be:
| 1. | |
2. | ![]() |
| 3. | \(\mathrm{CH_3NH_2 }\) |
4. | ![]() |
The products formed when aniline reacts with Br₂ water and NaNO₂/HCl are, respectively:
| 1. | p-Bromoaniline; p-Chloroaniline |
| 2. | 2,4,6-Tribromoaniline; p-Chloroaniline |
| 3. | 2,4,6-Tribromoaniline; Benzenediazoniumchloride |
| 4. | p-Bromoaniline; Benzenediazoniumchloride |
Aniline when diazotized in cold and then treated with dimethyl aniline gives a coloured product. Its structure would be:
| 1. | |
| 2. | |
| 3. | |
| 4. |
Which chemical reaction leads to the formation of isocyanide?
1. Reimer Tiemann reaction.
2. Carbylamine reaction.
3. Hoffmann bromamide reaction.
4. None of the above.
The final product C, obtained in this reaction, would be:
| 1. | 2. | ||
| 3. | 4. |
A method for the identification of primary, secondary and tertiary amines is:
1. Azo-dye test
2. Carbylamine test
3. Hinsberg’s test
4. None of these
Aromatic primary amines cannot be prepared by Gabriel phthalimide synthesis because :
| 1. | Alkyl halides do not undergo electrophilic substitution with the anion formed by the phthalimide |
| 2. | Alkyl halides do not undergo nucleophilic substitution with the anion formed by the phthalimide |
| 3. | Aryl halides do not undergo nucleophilic substitution with the anion formed by the phthalimide |
| 4. | Aryl halides do not undergo electrophilic substitution with the anion formed by the phthalimide |
Predict the product formed when benzenediazonium chloride reacts with hypophosphorous acid and water.
C₆H₅N₂Cl + H₃PO₂ + H₂O → Product
1. C₆H₅NCThe primary amine is -
1.
2.
3.
4. None of the above
Which of the following is a secondary amine is -