NEET Chemistry The Solid State Questions Solved


Analysis shows that an oxide ore of  nickel has formula  Ni0.98O1.00. The percentage of nickel as Ni3+ ions is nearly

1. 2

2. 96

3. 4

4. 98

(3) The ratio Ni : O = 98:100

So, 100 atom of oxygen and 98 atom of Ni.

Let the number of atom Ni2+ = x

then number of Ni+3 =98-.x

(charge on Ni and O is equal)

So, then oxygen has charge =-2

3(98-x) + 2x = 2(100)

294-3x+2x=2(100)

-x=-94

x=94

% of Ni+2  = atoms of Ni+2total number of atoms of Ni×100

94/98*100 = 96%

Percentage of Ni+3 = 100 - 96 =4%

Difficulty Level:

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