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#26-Equations-for-Uniform-Acceleration
#27-Equations for Uniform Acceleration 28Calculus Method29
#28-Sign Convention
#29-Solved Examples 16
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#32-Solved Examples 19
#33-Solved Examples 20
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#30-Solved Examples 17

Concept Questions :-

Uniformly accelerated motion

Distance travelled in t second,

Here, initial velocity u=0h=gt22                                                         ......        (1)Distance travelled in nth second = u +a2(2n -1)Distance travelled in last second= 0 + g2(2t-1) =9h25     ..............(2)Equating h from equation 1 and 225g(2t-1)18=gt229t2 -50t +25 =0Solving for t,t =50 ±502-4×9×252×9 = 1018s or 5 sTime has to be greater than 1 second, so  t=5sPutting value of t in eqn. 1h=g522 = 122.5 m

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