NEET Questions Solved


0.5 mole of BaCl2 is reacted with 0.2 mole Na3PO4 then maximum moles of Ba3(PO4)2 formed is 

1. 0.33

2. 0.2

3. 0.1

4. 0.5

(3) 3BaCl2 + 2Na3PO4 Ba3(PO4)+6NaCl

0.5mole 0.2 mole

Na3PO4 is the limiting reagent

2 Mole Na3PO4  2 Mole Ba3(PO4)+6NaCl

0.2 Mole  Na3PO4 0.1 Mole Ba3(PO4)2

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