NEET Chemistry The Solid State Questions Solved


Oxygen atoms forms fcc unit cell with 'A' atoms occupying all tetrahedral voids and 'B' atoms occupying all octahedral voids. If atoms are removed from two of the body diagonals then determine the formula of resultant compound formed.

1. A4B4O7

2. A8B6O7

3. A8B8O7

4. A6B8O6

(2) originally, Number of oxygen atoms = 1/8x8+1/2x6 = 1+3 = 4 atoms

Number of 'A' atoms = 8

Numbe of 'B' atoms = 1/4x12+1=3+1=4atoms

After removal of atoms from two body diagonals are- 

Number of oxygen atoms = 4-1/8x4 = 4-1/2 =7/2

Number of 'A' atoms = 8-4 = 4

Numbe of 'B' atoms = 4-1 = 3

Hence, the formula of the compound is 

A4B3O7/2  or A8B6O7

Difficulty Level:

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