In the presence of peroxide, hydrogen chloride and hydrogen fluoride do not undergo anti-Markovnikov's

addition reaction with alkenes because-

1. Both are highly ionic

2. One is oxidizing and the other is reducing

3. One of the steps is endothermic in both the cases

4. All the steps are exothermic in both cases

In the reaction sequence (A) will be

$\underset{Anhy. AlC{l}_3}{\overset{HBr}{\to }}\left[A\right]$

1. 1-Bromo-2-ethyl cyclopentane

2. 1-Bromo-1-methyl cyclopentane

3. 1-Bromo-5-methyl cyclopentane

4. 5-Bromo-1-methyl cyclopentane

The reaction of propene with HOCl proceeds via the addition of-

The compound among the following that yield propyne on hydrolysis is:

1. ${\mathrm{Al}}_4{\mathrm{C}}_3$

2. ${\mathrm{Mg}}_2{\mathrm{C}}_3$

3. ${\mathrm{B}}_4\mathrm{C}$

4. ${\mathrm{La}}_4{\mathrm{C}}_3$

Hydrogenation of the above compound in the presence of poisoned palladium catalyst gives

(1) optically active compound

(2) an optically inactive compound

(3) a racemic mixture

(4) a diastereomeric mixture

The reaction of HBr with 

 in the presence of peroxide will give:

1.
2.
3.
4.

The product formed on reaction of HBr with propene is-

1. 1-bromopropane

2. 2-bromopropane

3. 3-bromopropane

4. no reaction occurs

An alkene among the following that reacts fastest with H₂ under catalytic conditions is -

1.		2.
3.		4.

Propyne and propene can be distinguished by ,

(1) conc. H₂SO₄

(2) Br₂ in CCl₄

(3) diluted H₂SO₄

(4) AgNO₃ in ammonia

The product(s) obtained via oxymercuration (HgSO₄ + H₂SO₄ ) of but-1-yne is -

1. ${\mathrm{CH}}_3{\mathrm{CH}}_2-\stackrel{\stackrel{\mathrm{O}}{\left|\right|}}{\mathrm{C}}-{\mathrm{CH}}_3$

2. CH₃CH₂ CH₂-CHO

3. CH₃CH₂CHO + HCHO

4. CH₃ CH₂COOH + HCOOH