A man starts from point 'P' and goes 20 m due East, then 5 m due North, then 35 m due West, and finally 25 m due South. His displacement from point 'P' is:
1. | 25 m at \(\tan^{-1}(\frac{4}{3})\) west of south. |
2. | 85 m in south-west. |
3. | 25 m at \(\tan^{-1}(\frac{3}{4})\) west of south. |
4. | 15 m at \(\tan^{-1}(\frac{3}{4})\) west of south |
An aircraft is flying horizontally at a height of 1 km from the ground with a speed of 200 m/s. An anti-craft missile launcher kept at a point on the ground which is in the vertical plane of the motion of aircraft. The muzzle velocity of the missile is 600 m/s. The missile is fired at a time when the aircraft was vertically above the anti-craft missile launcher. At what angle with horizontal should it be fired so as to hit the aircraft?
(1)
(2)
(3)
(4) Just vertically upward
A man can throw a stone to a maximum height 'h'. The greatest horizontal distance up to which he can throw the stone is
(1) h
(2) 2h
(3)
(4) 4h
An oblique projectile is projected with a speed u. It takes time t, to reach the maximum height and time t, to come back to the ground. Air resistance is not neglected, then is
(1) > 1
(2) < 1
(3) = 1
(4) Depends on the angle of projection
The speed of a projectile projected from level ground at its maximum height is found to be half of its speed of projection (u). Its maximum height is:
1.
2.
3.
4.
A body moved along x-axis and y-axis according to the equation,
What is the trajectory followed by the body?
1.
2.
3.
4.
A particle of mass \(m\) is projected with a velocity at an angle with the horizontal into a uniform gravitational field. The slope of the trajectory varies with horizontal distance \(x\) as:
1. | 2. | ||
3. | 4. |
A projectile thrown at an angle 30° with horizontal from the level ground reaches a maximum height of 20 m. What will be the maximum height if it is thrown at an angle 60° with the same speed?
(1) 20 m
(2) 30 m
(3) 50 m
(4) 60 m
A body moving in a uniform circular motion with speed v. The magnitude of the change in its velocity after it rotates by an angle 120° is:
1. \(2v\)
2. \(\sqrt{3}v\)
3. \(v\)
4. \(\frac{\sqrt{3}}{2}v\)
A car moves on a circular path such that its speed is given by v = Kt, where K =constant and t is time. Also given: radius of the circular path is r. The net acceleration of the car at time t will be:
1.
2. 2K
3. K
4.