Atomic weight of boron is 10.81 and it has two isotopes ${}_5{}^{10}B<mspace\; width="1em"></mspace>and<mspace\; width="1em"></mspace>{}_5{}^{11}B$. Then, the ratio of atoms of  ${}_5{}^{10}B<mspace\; width="1em"></mspace>and<mspace\; width="1em"></mspace>{}_5{}^{11}B$ in nature would be 

1. 19 : 81

2. 10 : 11 

3. 15 : 16 

4. 81 : 19

The half-life of radium is 1600 yr.  The fraction of a sample of radium that would remain

after 6400 yr 

1. $\frac{1}{4}$   

2. $\frac{1}{2}$ 

3. $\frac{1}{8}$ 

4. $\frac{1}{16}$

The count rate of a Geiger Muller counter for the radiation of a radioactive material of half-life 30 min decreases to 5 $s^{-1}$ after 2 h. The initial count rate was 

1. 20 $s^{-1}$ 

2. 25 $s^{-1}$ 

3. 80 $s^{-1}$ 

4. 625 $s^{-1}$

The radius R of a nuclear matter varies with A as

1. $R<mspace\; width="1em"></mspace>\alpha <mspace\; width="1em"></mspace>A^{2/3}$

2. $R<mspace\; width="1em"></mspace>\alpha <mspace\; width="1em"></mspace>A^{1/3}$

3. $R<mspace\; width="1em"></mspace>\alpha <mspace\; width="1em"></mspace>A^0$ 

4. $R<mspace\; width="1em"></mspace>\alpha <mspace\; width="1em"></mspace>A$

Number of nuclei of a radioactive substance at time t = 0 are 2000 and 1800 at time t = 2s. Number of nuclei left after t = 6s is 

1. 1442 

2. 1554 

3. 1652 

4. 1458

In a radioactive material, the activity at time $t_1$ is $R_1$ and at a later time, $t_2$ is $R_2$. If the decay constant of the material is $\lambda$, then:

1. $R_1=R_2{e}^{-\lambda \left(t_1-t_2\right)}$   

2. $R_1=R_2{e}^{\lambda \left(t_1-t_2\right)}$

3. $R_1=R_2\left(\frac{t_2}{t_1}\right)$ 

4. $R_1=R_2$

Which of the following are suitable for the fusion process ? 

1. Light nuclei

2. Heavy nuclei

3. Elements lying in the middle of periodic table

4. Elements lying in the middle of binding energy curve

In the nuclear reaction: \(\mathrm{X}\left(n,\alpha\right){}_{3}^{7}\mathrm{Li}\) the term \({X}\) will be:

Two radioactive substances A and B have decay constants $5\lambda$ and $\lambda$ respectively. At t=0 they have the same number of nuclei. The ratio of number of nuclei of A to those of B will be ${\left(\frac{1}{e}\right)}^2$ after a time interval

1. $\frac{1}{4\lambda }$   

2. $4\lambda$

3. $2\lambda$ 

4. $\frac{1}{2\lambda }$