A block slides down an inclined plane of inclination \(30^{\circ}\) with a constant velocity. It then projected up with an initial speed of \(6~\text{m/s}\), the distance moved by it on the inclined before coming to rest is:
1. \(1.5~\text{m}\)
2. \(1.8~\text{m}\)
3. \(2.0~\text{m}\)
4. \(2.4~\text{m}\)
The potential energy of a particle of mass 0.5 kg moving along x axis is given by
U = 2x (x - 3). The speed of the particle is maximum at
(1) x = 1 m
(2) x = 1.5 m
(3) X = 2 m
(4) x = 3 m
Work energy theorem is valid in
(1) Only inertial frame of reference
(2) The only non-inertial frame of reference
(3) Both inertial and non-inertial frame of reference
(4) Does not depend on any frame of reference
A block of mass m is projected with speed v along the rough surface of an inclined plane of height h. If block comes to rest at the top of the surface, then work done by friction force is
1.
2.
3. -mgh
4.
1. | \(0\%\) | 2. | \(25\%\) |
3. | \(50\%\) | 4. | \(100\%\) |
If a body starts its motion along the smooth track from P as shown in the figure, then its velocity at the instant of leaving R is
(1) 5 m/s
(2) 15 m/s
(3) 10 m/s
(4) 20 m/s
The principle of conservation of energy and conservation of mechanical energy applicable respectively for
(1) Conservative and non-conservative forces
(2) Conservative and conservative force
(3) Non-conservative and conservative forces
(4) All forces and conservative forces
A particle of mass m is moving in a vertical circle of radius r. If the velocity of the particle at the uppermost point is , then its velocity at the lowermost point
(1)
(2)
(3)
(4) 2
A person applies a force \(\vec F\) on a box inside a moving train. If \(S_1\) is the displacement of box with respect to train and
1. \(\vec F \cdot \vec{S_1}\)
2. \(\vec F \cdot \vec{S_2}\)
3. \(\vec F \cdot (\vec{S_1}+ \vec{S_2})\)
4. \(\vec F \cdot (\vec{S_1}- \vec{S_2})\)
A block having mass m is hanging by a string of length l. A variable horizontal force is applied on the block, which displaces the block slowly till the string makes an angle with the vertical. Find the work done by the force.
(1) mgl
(2) mgl(1 - cos)
(3) mglcos
(4) mgl(1 + cos)