A motorcyclist going round in a circular track at constant speed has:

(1) constant linear velocity

(2) constant acceleration

(3) constant angular velocity

(4) constant force

Subtopic:  Circular Motion |
 66%
From NCERT
To view explanation, please take trial in the course.
NEET 2023 - Target Batch - Aryan Raj Singh
Hints
To view explanation, please take trial in the course.
NEET 2023 - Target Batch - Aryan Raj Singh

A particle P is moving in a circle of radius ‘a’ with a uniform speed v. C is the centre of the circle and AB is a diameter. When passing through B, the angular velocity of P about A and C are in the ratio 

(1) 1 : 1

(2) 1 : 2

(3) 2 : 1

(4) 4 : 1

Subtopic:  Circular Motion |
 56%
From NCERT
To view explanation, please take trial in the course.
NEET 2023 - Target Batch - Aryan Raj Singh
Hints
To view explanation, please take trial in the course.
NEET 2023 - Target Batch - Aryan Raj Singh

The angular speed of a fly wheel making \(120\) revolutions/minute is:
1. \(2\pi~\mathrm{rad/s}\)
2. \(4\pi^2~\mathrm{rad/s}\)
3. \(\pi~\mathrm{rad/s}\)
4. \(4\pi~\mathrm{rad/s}\)

Subtopic:  Circular Motion |
 82%
From NCERT
PMT - 1995
To view explanation, please take trial in the course.
NEET 2023 - Target Batch - Aryan Raj Singh
Hints
To view explanation, please take trial in the course.
NEET 2023 - Target Batch - Aryan Raj Singh

advertisementadvertisement

Certain neutron stars are believed to be rotating at about 1 rev/s. If such a star has a radius of 20 km, the acceleration of an object on the equator of the star will be:

1. \(20 \times 10^8 \mathrm{~m} / \mathrm{s}^2 \) 2. \(8 \times 10^5 \mathrm{~m} / \mathrm{s}^2 \)
3. \(120 \times 10^5 \mathrm{~m} / \mathrm{s}^2 \) 4. \(4 \times 10^8 \mathrm{~m} / \mathrm{s}^2\)
Subtopic:  Circular Motion |
 69%
From NCERT
To view explanation, please take trial in the course.
NEET 2023 - Target Batch - Aryan Raj Singh
Hints
Links
To view explanation, please take trial in the course.
NEET 2023 - Target Batch - Aryan Raj Singh

An electric fan has blades of length 30 cm as measured from the axis of rotation. If the fan is rotating at 1200 r.p.m, the acceleration of a point on the tip of the blade is about

(1) 1600 m/sec2

(2) 4740 m/sec2

(3) 2370 m/sec2

(4) 5055 m/sec2

Subtopic:  Circular Motion |
 79%
From NCERT
PMT - 1990
To view explanation, please take trial in the course.
NEET 2023 - Target Batch - Aryan Raj Singh
Hints
To view explanation, please take trial in the course.
NEET 2023 - Target Batch - Aryan Raj Singh

If ar and at represent radial and tangential accelerations, the motion of a particle will be uniformly circular if 

1. ar = 0 and at = 0

2. ar = 0 but at0

3. ar0 but at = 0

4. ar0 and at0

Subtopic:  Circular Motion |
 71%
From NCERT
PMT - 2004
To view explanation, please take trial in the course.
NEET 2023 - Target Batch - Aryan Raj Singh
Hints
To view explanation, please take trial in the course.
NEET 2023 - Target Batch - Aryan Raj Singh

advertisementadvertisement

In 1.0 s, a particle goes from point A to point B, moving in a semicircle of radius 1.0 m (see figure). The magnitude of the average velocity is:
                   

1. 3.14 m/s 2. 2.0 m/s
3. 1.0 m/s 4. Zero
Subtopic:  Speed & Velocity |
 76%
From NCERT
To view explanation, please take trial in the course.
NEET 2023 - Target Batch - Aryan Raj Singh
Hints
Links
To view explanation, please take trial in the course.
NEET 2023 - Target Batch - Aryan Raj Singh

The coordinates of a moving particle at any time \(t\) are given by \(x=\alpha t^3\) and \(y=\beta t^3.\) The speed of the particle at time \(t\) is given by:
1. \(\sqrt{\alpha^2+\beta^2}~\)
2. \(3t\sqrt{\alpha^2+\beta^2}~\)
3. \(3t^2\sqrt{\alpha^2+\beta^2}~\)
4. \(t^2\sqrt{\alpha^2+\beta^2}~\)

Subtopic:  Speed & Velocity |
 82%
From NCERT
To view explanation, please take trial in the course.
NEET 2023 - Target Batch - Aryan Raj Singh
Hints
To view explanation, please take trial in the course.
NEET 2023 - Target Batch - Aryan Raj Singh

Figure shows a body of mass m moving with a uniform speed v along a circle of radius r. The change in velocity in going from A to B is 

(1) v2

(2) v/2

(3) v

(4) zero

Subtopic:  Circular Motion |
 65%
From NCERT
PMT - 2004
To view explanation, please take trial in the course.
NEET 2023 - Target Batch - Aryan Raj Singh
Hints
To view explanation, please take trial in the course.
NEET 2023 - Target Batch - Aryan Raj Singh

advertisementadvertisement

The angle turned by a body undergoing circular motion depends on the time as given by the equation, θ=θ0+θ1t+θ2t2. It can be deduced that the angular acceleration of the body is? 

1. θ1

2. θ2

3. 2θ1

4. 2θ2

Subtopic:  Circular Motion |
 84%
From NCERT
To view explanation, please take trial in the course.
NEET 2023 - Target Batch - Aryan Raj Singh
Hints
Links
To view explanation, please take trial in the course.
NEET 2023 - Target Batch - Aryan Raj Singh