The displacement y of a particle executing periodic motion is given by y=4cos2t/2sin1000t. This expression may be considered to be a result of the superposition of  ........... independent harmonic motions

1. Two         

2. Three

3. Four         

4. Five

Subtopic:  Simple Harmonic Motion |
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A particle of mass m is attached to three identical springs A, B and C each of force constant k a shown in figure. If the particle of mass m is pushed slightly against the spring A and released then the time period of oscillations is -

(a) 2π2mk          (b) 2πm2k

(c) 2πmk            (d) 2πm3k

              

                 

Subtopic:  Combination of Springs |
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The graph shows the variation of displacement of a particle executing S.H.M. with time. We infer from this graph that -

          

(1) The force is zero at time T/8

(2) The velocity is maximum at time T/4

(3) The acceleration is maximum at time T

(4) The P.E. is equal to total energy at time T/4

Subtopic:  Energy of SHM |
 67%
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For a particle executing S.H.M. the displacement x is given by Acosωt. Identify the graph which represents the variation of potential energy (P.E.) as a function of time t and displacement x.

      

(a) I, III          (b) II, IV

(c) II, III         (d) I, IV

Subtopic:  Energy of SHM |
 56%
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The velocity-time diagram of a harmonic oscillator is shown in the figure given below. The frequency of oscillation will be:
                  

1. \(25~\text{Hz}\)
2. \(50~\text{Hz}\)
3. \(12.25~\text{Hz}\)
4. \(33.3~\text{Hz}\)

Subtopic:  Simple Harmonic Motion |
 74%
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The variation of the potential energy of the harmonic oscillator is shown in the figure. The spring constant will be:
           
1. \(1\times10^{2}~\text{N/m}\)
2. \(150~\text{N/m}\)
3. \(0.667\times10^{2}~\text{N/m}\)
4. \(3\times10^{2}~\text{N/m}\)
Subtopic:  Energy of SHM |
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A body performs S.H.M. . Its kinetic energy K varies with time t as indicated by graph

(a)    (b) 

(c)      (d) 

 

Subtopic:  Energy of SHM |
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The amplitude of a damped oscillator decreases to 0.9 times its original magnitude in 5 s. In another 10 s, it will decrease to α times its original magnitude, where α equals

1. 0.7

2. 0.81

3. 0.729

4. 0.6

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A particle performs SHM on x-axis with amplitude A and time period T. The time taken by the particle to travel a distance A5 starting from rest is

1. T20

2. T2πcos-145

3. T2πcos-115

4. T2πsin-115

Subtopic:  Simple Harmonic Motion |
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Two simple pendulums of length 5 m and 20 m respectively are given small linear displacement in one direction at the same time. They will again be in the phase when the pendulum of shorter length has  completed how many oscillations?

1. 5

2. 1

3. 2

4. 3

Subtopic:  Simple Harmonic Motion |
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