Identify (X) in the sequence :
1.
2.
3.
4.
To unlock all the explanations of 20 chapters you need to be enrolled in MasterClass Course.
To unlock all the explanations of 20 chapters you need to be enrolled in MasterClass Course.
1-propanol and 2-propanol can be best distinguished by:
1. | Oxidation with alkaline KMnO4 followed by reaction with Fehling solution. |
2. | Oxidation with acidic dichromate followed by reaction with Fehling solution. |
3. | Oxidation by heating with copper followed by reaction with Fehling solution. |
4. | Oxidation with conc. H2SO4 followed by reaction with Fehling solution. |
To unlock all the explanations of 20 chapters you need to be enrolled in MasterClass Course.
To unlock all the explanations of 20 chapters you need to be enrolled in MasterClass Course.
Which among the following compounds is most acidic
in character :
1. HOH
2. CH3OH
3. CH3CH2OH
4.
To unlock all the explanations of 20 chapters you need to be enrolled in MasterClass Course.
To unlock all the explanations of 20 chapters you need to be enrolled in MasterClass Course.
Which is more acidic?
1. o-Cresol
2. p-Nitrophenol
3. Phenol
4. m-Cresol
To unlock all the explanations of 20 chapters you need to be enrolled in MasterClass Course.
To unlock all the explanations of 20 chapters you need to be enrolled in MasterClass Course.
The compound Y in the above sequence is
1. 2-Methyl-2-phenyl-1-propanol
2. 2-Phenyl-2-propanol
3. Acetophenone
4. 2-Methyl-1-Phenyl-2-propanol
To unlock all the explanations of 20 chapters you need to be enrolled in MasterClass Course.
To unlock all the explanations of 20 chapters you need to be enrolled in MasterClass Course.
The major product C and D formed in the following reaction respectively are:
H3C-CH2-CH2-OC(CH3)3C+D
1. and I-C(CH3)3
2. and I-C(CH3)3
3. and HO-C(CH3)3
4. and HO-C(CH3)3
When vapour of a secondary alcohol is passed over heated copper at 573 K, the product formed is-
1. A carboxylic acid
2. An aldehyde
3. A ketone
4. An alkene
The compound that is most difficult to protonate is:
1.
2.
3.
4.
Ethylene oxide when treated with Grignard reagent yields :
1. Secondary alcohol
2. Tertiary alcohol
3. Cyclopropyl alcohol
4. Primary alcohol
The general molecular formula, that represents the homologous serious of alkanols is:
1. \(C_{n} H_{2 n} O_{2}\)
2. \(C_{n} H_{2 n} O\)
3. \(C_{n} H_{2 n + 1} O\)
4. \(C_{n} H_{2 n + 2} O\)
To unlock all the explanations of 20 chapters you need to be enrolled in MasterClass Course.
To unlock all the explanations of 20 chapters you need to be enrolled in MasterClass Course.