Q. No.In which genetic condition, each cell in the affected person, has three sex chromosomes XXY?
1. Thalassemia
2. Klinefelter's Syndrome
3. Phenylketonuria
4. Turner's Syndrome
The production of gametes by the parents the formation of zygotes, the F1 and F2 plants can be understood using
| 1. | Pie diagram | 2. | A pyramid diagram |
| 3. | Punnett square | 4. | Wenn diagram |
In a marriage between a male with blood group A and a female with blood group B, the progeny had either blood group AB or B. What could be the possible genotype of the parents?
1. IA i (Male) ; IB IB (Female)
2. IA IA (Male) ; IB IB (Female)
3. IA IA (Male) ; IB i (Female)
4. IA i (Male) ; IB i(Female)
Match the items of Column-I with Column-II:
| Column-I | Column-II | ||
| (a) | XX-XO method of sex determination | (i) | Turner's syndrome |
| (b) | XX-XY method of sex Determination | (ii) | Female heterogametic |
| (c) | Karyotype-45 | (iii) | Grasshopper |
| (d) | ZW-ZZ method of Sex Determination | (iv) | Female homogametic |
Select the correct option from the following:
| (a) | (b) | (c) | (d) | |
| 1. | (ii) | (iv) | (i) | (iii) |
| 2. | (i) | (iv) | (ii) | (iii) |
| 3. | (iii) | (iv) | (i) | (ii) |
| 4. | (iv) | (ii) | (i) | (iii) |
Match each item in Column I with one in Column II and select your answer from the codes given:
| Column I | Column II | ||
| Scientist | Contribution | ||
| A. | Francis Crick | a. | Breaking the genetic code |
| B. | Nirenberg | b. | Established Coenorhabditiselegans as a model genetics study organism |
| C. | Benzer | c. | Central dogma of molecular biology |
| D. | Brenner | d. | Bacteriophage genetics |
Codes:
| A. | B. | C. | D. | |
| 1. | c | a | d | b |
| 2. | c | a | b | d |
| 3. | a | b | c | d |
| 4. | a | c | d | b |
Monosomy means:
1. Lack of one pair of chromosomes
2. Lack of one of any one pair of chromosome
3. Presence of an extra chromosome
4. Presence of an extra set of chromosomes
In cases of Phenylketonuria:
1. The affected individual lacks an enzyme that converts the amino acid tyrosine into phenylalanine.
2. The affected individual makes an enzyme that converts the amino acid tyrosine into phenylalanine.
3. The affected individual makes an enzyme that converts the amino acid phenylalanine into tyrosine.
4. The affected individual lacks an enzyme that converts the amino acid phenylalanine into tyrosine.
The point mutation leading to sickle cell anaemia occurs:
1. at sixth position in the beta chain of haemoglobin
2. at sixth position in the alpha chain of haemoglobin
3. at sixth position in the beta chain of myoglobin
4. at sixth position in the alpha chain of myoglobin
Mendelian disorders are mainly determined by:
1. Alteration or mutation in a single gene.
2. Chromosomal gross structural changes.
3. Recombination between linked genes.
4. Jumping genes
‘When two pairs of traits are combined in a hybrid, segregation of one pair of characters is independent of the other pair of characters’. This is the statement of:
1. Law of Dominance
2. Law of segregation
3. Law of Independent Assortment
4. Law of Linkage
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