The product which cannot be formed is:

1.
2.
3.
4.

The product formed in this reaction is

1.          2.  

3.           4.  

Reaction equilibrium will shift towards the right in:

1.		2.
3.		4.

1.             

2.  

3.       

4.  

The Wolf Kishner's reduction cannot be applied to:

1.		2.
3.		4.

The correct order of acidity of the following compounds is:

1. 1 > 2 > 3

2. 1 > 3 > 2

3. 3 > 1 > 2

4. 3 > 2 > 1

 The reddish-brown precipitate formed in Fehling's test for aldehydes (RCHO) is due to the formation of the following compound :
1. \(\mathrm{Cu}\)
2. \(\mathrm{Cu}_2 \mathrm{O}\)
3. \(\mathrm{CuO}\)
4. \((\mathrm{RCOO})_2 \mathrm{Cu}\)

The major final product in the following reaction is

${\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{CN}\underset{\left(2\right){\mathrm{H}}_3{\mathrm{O}}^{+}}{\overset{\left(1\right){\mathrm{CH}}_3\mathrm{MgBr}}{\to }}$

1.        2.  

3.       4.  

4-Formylbenzoic acid on treatment with one equivalent of hydrazine followed by heating with alcoholic KOH gives, as major product:

1.		2.
3.		4.

In the given below reaction

x, y, and z are: 

1.  x = Mg; dry ether; y = ${\mathrm{CH}}_3\mathrm{Cl}; \mathrm{z} = {\mathrm{H}}_2\mathrm{O}$

2.  x = Mg; dry methanol; $\mathrm{y} = {\mathrm{CO}}_2; \mathrm{z} = \mathrm{dil}.\mathrm{HCl}$

3.  x = Mg; dry ether; $\mathrm{y} = {\mathrm{CO}}_2; \mathrm{z} = \mathrm{dil}.\mathrm{HCl}$

4.  x = Mg; dry methanol; $\mathrm{y} = {\mathrm{CH}}_3\mathrm{Cl}; \mathrm{z} = {\mathrm{H}}_2\mathrm{O}$