Ncert Exercises & Solutions

4.4 The decomposition of dimethyl ether leads to the formation of CH4, H2 and CO and the reaction rate is given by

Rate = k [CH3OCH3]3/2

The rate of reaction is followed by increase in pressure in a closed vessel, so the rate can also be expressed in terms of the partial pressure of dimethyl ether, i.e.,

Rate=K $P C H_{3} O C H_{3})^{\frac{3}{2}}$

If the pressure is measured in bar and time in minutes, then what are the units of rate and rate constants?

NEETprep Answer:

pressure is measured in bar and time in minutes, then
Unit of rate = bar min $^{1}$

Rate =K ( $R a t e = K (P_{C H_{3} O C H_{3}})^{\frac{3}{2}}$
$\Rightarrow K = \frac{R a t e}{(P_{C H_{3 O C H_{3}}})^{3 / 2}}$

Therefore, unit of rate constants $K = \frac{b a r m i n^{- 1}}{b a r^{3 / 2}}$
$= b a r^{\frac{- 1}{2}} m i n^{- 1}$

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