Q.9  Calculate the number of kJ of heat necessary to raise the temperature of 60.0 g of aluminum from 35°C to 55°C. Molar heat capacity of Al is 24 J mol-1 K-1.

NEETprep Answer:

From the expression of heat (q),
q = m. c. ∆T Where,
c = molar heat capacity m
= mass of the substance
∆T = change in temperature
Substituting the values in the expression of q:

q=6027mol24 J mol-1 K-120 K

q = 1066.7 J q
= 1.07 kJ