Ncert Exercises & Solutions

4.8 A closely wound solenoid 80 cm long has 5 layers of windings of 400 turns each. The diameter of the solenoid is 1.8 cm. If the current carried is 8.0 A, estimate the magnitude of B inside the solenoid near its centre.

NEETprep Answer:

Length of the solenoid, I = 80 cm = 0.8 m

There are five layers of windings of 400 turns each on the soelnoid.

∴

Total number of turns on the solenoid, N = 5

\times

400 = 2000

Diameter of the solenoid, D = 1.8 cm = 0.018 m

Current carried by the solenoid, I = 8.0 A

Magnitude of the magnetic field inside the solenoid near its centre is given by the relation,

B = \frac{μ_{0} NI}{l}

where, μ_{0} = Permeability of free space = 4 π \times 10^{- 7} T m A^{- 1}

B = \frac{4 π \times 10^{- 7} \times 2000 \times 8}{0.8} = 2.5 \times 10^{- 2} T

Hence, the magnitude of the magnetic field inside the solenoid near its centre is

2.512 \times 10^{- 2} T

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