Ncert Exercises & Solutions

4.6 A 3.0 cm wire carrying a current of 10 A is placed inside a solenoid perpendicular to its axis. The magnetic field inside the solenoid is given to be 0.27 T. What is the magnetic force on the wire?

NEETprep Answer:

Length of the wire, l = 3 cm = 0.03 m

Current flowing in the wire, I = 10 A

Magnetic field, B = 0.27 T

Angle between the current and magnetic field,

θ = 90 °

Magnetic force exerted on the wire is given as:

F = BI l sinθ = 0.27 \times 10 \times 0.03 \sin 90 ° = 8.1 \times 10^{- 2} N

Hence, the magnetic force on the wire is

8.1 \times 10^{- 2} N

. The direction of the force can be obtained from Fleming's left hand rule.

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