Ncert Exercises & Solutions

4.5 What is the magnitude of magnetic force per unit length on a wire carrying a current of 8 A and making an angle of 30º with the direction of a uniform magnetic field of 0.15 T?

NEETprep Answer:

Current in the wire, I = 8 A

Magnitude of the uniform magnetic field, B = 0.15 T

Angle between the wire and magnetic field,

θ = 30 °

Magnetic force per unit length on the wire is given as:

f = BI sinθ = 0.15 \times 8 \times 1 \times \sin 30 ° = 0.6 N m^{- 1}

Hence, the magnetic force per unit length on the wire is

0.6 N m^{- 1}

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