4.16 A cricketer can throw a ball to a maximum horizontal distance of 100 m. How much high above the ground can the cricketer throw the same ball?

 

NEETprep Answer:
For maximum range, θ=450
Since, R=u2sin2θg
Rmax=u2sin900g=u2g
100=u2g   .....1
H=u2sin2θ2g
Hmax=u2sin29002g
Hmax=u22g   .....2
From 1 and 2,
Hmax=1002=50 m