Ncert Exercises & Solutions

A hydrocarbon of molecular mass 72 g mol $^{- 1}$ gives a single monochloro derivative and two dichloro derivatives on photo chlorination. Give the structure of the hydrocarbon.

Since, the molar mass of hydrocarbon is 72 g mol

^{- 1}

hence the hydrocarbon is C

ie,, pentane.

On chlorination in the presence of light, it gives monochlorinated derivatives so, all the hydrogen atoms must be

equivalent and the structure of the compound will be

$C H_{3} C H_{3}$
$| |$
$H_{3} C C C H_{3} \to_{h v}^{C l_{2}} H_{3} C — C — C H_{2} C l$
$| |$
$C H_{3} C H_{3}$
$2, 2 d i m e t h y l p r o p a n e 1 - c h l o r o 2, 2 - d i m e t h y l p r o p a n e$
$(M o n o c h l o r o d e r i v a t e)$
$C H_{3} C H_{3}$
$| |$
$H_{3} C — C — C H_{3} \to_{h v}^{C l_{2}} H_{3} C — C — C H_{2} C l o r C l — H_{2} C — C — C H_{2} C l$
$| | |$
$C H_{3} C H_{3} C H_{3}$
$2, 2 - d i m e t h y l o p r o p n e 1, 1 - D i c h l o r o -; 1, 3 - d i c h l o r o - 2,$
$2 - D i m e t h y l p r o p a n e 2 - d i m e t h l p r o p a n e$
$(D i c h l o r o d e r i v a t i v e) (D i c h l o r o d e r i v a t i v e)$

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