Ncert Exercises & Solutions

9.23 Give the oxidation state, d orbital occupation, and coordination number of the central metal ion in the following complexes:

(i) K₃[Co(C₂O₄)₃] (iii) (NH₄)₂[CoF₄]

(ii) cis-[CrCl₂(en)₂]Cl (iv) [Mn(H₂O)₆]SO₄

(i) K₃[Co(C₂O₄)₃]

The central metal ion is Co.
Its coordination number is 6 because three didentate ligand is attached to it.

Calculate the oxidation state is as follows:
The oxidation state can be given as:
x − 6 = −3
= + 3

T h e d o r b i t a l o c c u p a t i o n f o r C o^{3 +} i s t_{2} g^{6} e g^{0}

(ii) cis-[CrCl₂(en)₂]Cl

The central metal ion is Cr.

The coordination number is 6.

The oxidation state can be given as:
x + 2(0) + 2(−1) = +1
x − 2 = +1
x = +3

The d orbital occupation for

C r^{3 +} i s {t_{2 g}}^{3}

(iii) (NH₄)₂[CoF₄]

The central metal ion is Co.
The coordination number is 4.
The oxidation state can be given as:

x − 4 = −2
= +2

The d orbital occupation is e⁴t₂³

(iv) [Mn(H₂O)₆]SO₄

The central metal ion is Mn. The coordination number is 6. The oxidation state can be given as-
x + 0 = +2
X = +2

The orbital occupation is t_2g³e_g²

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