Ncert Exercises & Solutions

Calculate the number of unpaired electrons in the following gaseous ions: Mn3+, Cr3+, V3+ and Ti3+. Which one of these is the most stable in aqueous solution?

The ions with number of unpaired electrons is as follows:

Ions	electronic configuration	Number of unpaired electrons
Mn³⁺	[Ar] 3d⁴	4
Cr³⁺	[Ar] 3d³	3
V³⁺	[Ar] 3d²	2
Ti³⁺	[Ar] 3d¹	1

The most stable ions in an aqueous solution is Cr³⁺ because in presence of water ligand 3d orbital of Cr gets split into two levels, t_2g and e_g. Thus, all the three electrons are present in lower level that is t_2g and it stabilized the Cr³⁺ ion.

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