Ncert Exercises & Solutions

The oxidation state of the central atom in the anion of the compound ${NaH}_{2} {PO}_{2}$ will be-

1. +3

2. +5

3. +1

4. -3

Hint: The range of oxidation states shown by P is -3 to +5

Let the oxidation state of P in

{NaH}_{2} {PO}_{2}

is x.

1 + 2 \times 1 + x + 2 \times - 2 = 0

1 + 2 + x - 4 = 0

+ x - 1 = 0

x = + 1