Ncert Exercises & Solutions

Describe the shapes of $B F_{3} a n d B {H_{4}}^{-}$
. Assign the hybridization of boron in these species.

(i)

B F_{3}

As a result of its small size and high electronegativity, boron tends to form monomeric covalent halides. These halides have a planar triangular geometry. This triangular shape is formed by the overlap of three

s p^{2}

hybridised orbitals of boron with the sp orbitals of three halogen atoms. Boron is sp² hybridised in

B F_{3}

(ii) $B {H_{4}}^{-}$ Boron-hydride ion ( $B {H_{4}}^{-}$ ) is formed by the $s p^{3}$ hybridisation of boron orbitals. Therefore, it is a tetrahedral in structure.

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