Consider the compounds, . How will they behave with water? Justify.

Being a Lewis acid, $BC{I}_{3}$ readily undergoes hydrolysis. Boric acid is formed as a result. $BC{I}_{3}+3{H}_{2}O\to 3HCI+B{\left(OH\right)}_{3}$
$CC{I}_{4}$completely resists hydrolysis. Carbon does not have any vacant orbital. Hence, it cannot accept electrons from water to form an intermediate. When CCl4 and water are mixed, they form separate layers.