Consider the compounds, BCI3 and CCI4. How will they behave with water? Justify.

Being a Lewis acid, BCI3 readily undergoes hydrolysis. Boric acid is formed as a result. BCI3+3H2O3HCI+B(OH)3
CCI4completely resists hydrolysis. Carbon does not have any vacant orbital. Hence, it cannot accept electrons from water to form an intermediate. When CCl4 and water are mixed, they form separate layers. CCI4+H2ONo reaction