Ncert Exercises & Solutions

At the equilibrium position in the process of adsorption ..........

1. ΔH > 0

2. ΔH = TΔS

3. ΔH > TΔS

4. ΔH < TΔS

HINT: At equilibrium ,

∆ G = 0

Explanation:

As we know that, at equilibrium ΔG=0

We know that ; $∆ G = ∆ H - T ∆ S$

$\Rightarrow$ ΔH−TΔS = 0

$\Rightarrow$ ∆H = T∆S

Hence, at equilibrium enthalpy changes equal to product of temperature and entropy change.