Ncert Exercises & Solutions

In a reaction if the concentration of reactant A is tripled, the rate of reaction becomes twenty-seven times. What is the order of the reaction?

The rate of any elementary reaction can be represented as

$r = k [A]^{n}$

After changing concentration to its triple value A = 3A, r becomes 27

$\begin{array}{l} 27 r = k [3 A]^{n} \\ \frac{r}{27 r} = \frac{k [A]^{n}}{k [3 A]^{n}} \\ \frac{1}{27} = [\frac{1}{3}]^{n} \Rightarrow [\frac{1}{3}]^{3} = [\frac{1}{3}]^{n} \end{array}$

Hence, n= 3
The order of the reaction is three.

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