Which of the following compounds are aromatic according to Huckekl's rule?

A. The compound has $8\mathrm{\pi }$ electrons. It will be non-aromatic. Both rings are non-benzenoid.
B. The compound is aromatic. It has $6{\mathrm{\pi e}}^{-}$ delocalised electron ($4{\mathrm{\pi e}}^{-}+2$ lone pair electrons), all the four carbon atoms and the N atom are sp2 hybridised.
C. The compound contains $6\mathrm{\pi }$ electrons but not in the ring hence it is non-aromatic.
D. $10{\mathrm{\pi e}}^{-}$ obeying Huckel rule and the ring is planar. It is aromatic.
E. In this compound one six membered planar ring has $6{\mathrm{\pi e}}^{-}$ although it has $8\mathrm{\pi }$ electrons in two rings. It is therefore aromatic.
F. It has $14\mathrm{\pi }$ electrons in conjugation and in the planar ring, Huckel rule is verified. It will be aromatic.