Write hydrocarbon radicals that can be formed as intermediates during monochlorination of 2-methylpropane? Which of them is more stable?

2-methylpropane gives two types of radicals.
Radical (I) is more stable because it is $3°$ is free radical and stabilised by nine hyperconjugative structures (as it has 9 $\mathrm{\alpha }$-hydrogens)
Radical (II) is less stable because it is $1°$ free radical and stabilised by only one hyperconjugative structure (as it has only 1 $\mathrm{\alpha }$-hydrogen)