The relative reactivity of 1°, 2° and 3° hydrogen's towards chlorination is 1 : 3.8 : 5. Calculate the percentages of all monochlorinated products obtained from 2-methylbutane.


The given organic compound is
This compound has 9 primary hydrogen, 2 secondary and one tertiary hydrogen atoms. The relative 1°, 2° and 3° hydrogen atoms chlorination is 1:3.8:5. Relative amount of product after chlorination=Number of hydrogen×relative reactivity
Relative   1° halide     2°halide        3°halideAmount     9×1=9   2×3.8=7.6    1×5=5
Total amount of mono chloro product=9+7.6+5=21.6
Percentage of 1° mono chloro product=921.6×100=41.7%
Percentage of 2° mono chloro product=7.621.6×100=35.2%
Percentage of 3° mono chloro product=521.6×100=23.1%