What will be the product obtained as a result of the following reaction and why?

When Friedel-Craft alkylation is carried out with higher alkyl halide, e.g., n-propyl chloride, then the electrophile n-propyl carbocation ($1°$carbocation) formed which rearranges to form more stable iso-propyl carbocation ($2°$carbocation). Afterward the main product iso-propyl benzene will be formed.