Which of the following compounds will not exist as resonance hybrid. Give reason for your answer.

1.  CH3OH

2.  R-CONH2

3.  CH3CH=CHCH2NH2


(a) CH3OH As it lacks π-electrons hence it will not exist as resonance hybrid.
(b) R-CONH2 Due to the presence of n-electrons on N and π-electrons on C=O bond, hence amide can be represented as a resonance hybrid of the following three resonating structures.
(c) CH3CH=CHCH2NH2 As the lone pair of electrons on the N-atom is not conjugated with the π-electrons of the double bond, thus, resonance is not possible and hence no resonance hybrid will exist.