Ncert Exercises & Solutions

Question 12.35
In the estimation of sulphur by Carius method, 0.468 g of an organic sulphur compound
afforded 0.668 g of barium sulphate. Find out the percentage of sulphur in the given
compound.

Total mass of organic compound = 0.468 g [Given]
Mass of barium sulphate formed = 0.668 g [Given]
1 mol of BaSO

_{4}

= 233 g of BaSO

_{4}

= 32 g of sulphur
Thus, 0.668 g of BaSO

_{4}

contains

\frac{32 \times 0.668}{233} g

of sulphur = 0.0917 g of sulphur
Therefore, percentage of sulphur

= \frac{0.0197}{0.468} \times 100

= 19.59 %
Hence, the percentage of sulphur in the given compound is 19.59 %.

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