A compound (A) of boron reacts with NMe3 to give an adduct (B) which on hydrolysis gives a compound (C) and hydrogen gas. Compound (C) is an acid. Identify the compounds A, B, and C. Give the reactions involved.


Since, compound (A) of boron reacts with NMe3 to form an adduct (B) thus, compound (A) is a Lewis acid. Since, adduct (B) on hydrolysis gives an acid (C) and hydrogen gas, therefore, (A) must be B2H6 and (C) must be boric acid.
B2H6Diborane (A)+2NMe3Adduct (B)2BH3NMe3Adduct (B)BH3NMe3(B)+3H2OH3BO3Boric acid (C)+NMe3+6H2