37. In the Solvay process, can we obtain sodium carbonate directly by treating in the solution containing ${\left({\mathrm{NH}}_{4}\right)}_{2}{\mathrm{CO}}_{3}$ with sodium chloride? Explain.

No, ${\left({\mathrm{NH}}_{4}\right)}_{2}{\mathrm{CO}}_{3}$ reacts with NaCl as
${\left({\mathrm{NH}}_{4}\right)}_{2}{\mathrm{CO}}_{3}+2\mathrm{NaCl}⇌{\mathrm{Na}}_{2}{\mathrm{CO}}_{3}+2{\mathrm{NH}}_{4}\mathrm{Cl}$
Because the products obtained ${\mathrm{Na}}_{2}{\mathrm{CO}}_{3}$ and ${\mathrm{NH}}_{4}\mathrm{Cl}$ are highly soluble and the equilibrium will not shift in forward direction.
That is why in the Solvay process, we cannot obtain sodium carbonate directly by treating the solution containg ${\left({\mathrm{NH}}_{4}\right)}_{2}{\mathrm{CO}}_{3}$ with sodium chloride.