Ncert Exercises & Solutions

37. In the Solvay process, can we obtain sodium carbonate directly by treating in the solution containing ${({NH}_{4})}_{2} {CO}_{3}$ with sodium chloride? Explain.

No,

{({NH}_{4})}_{2} {CO}_{3}

reacts with NaCl as

{({NH}_{4})}_{2} {CO}_{3} + 2 NaCl ⇌ {Na}_{2} {CO}_{3} + 2 {NH}_{4} Cl

Because the products obtained

{Na}_{2} {CO}_{3}

and

{NH}_{4} Cl

are highly soluble and the equilibrium will not shift in forward direction.

That is why in the Solvay process, we cannot obtain sodium carbonate directly by treating the solution containg

{({NH}_{4})}_{2} {CO}_{3}

with sodium chloride.

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