Ncert Exercises & Solutions

Using the standard electrode potentials of the redox couples given below, which of the following is the strongest oxidizing agent?

$E^{⊝} values : {Fe}^{3 +} / {Fe}^{2 +} = + 0 . 77 V$
$I_{2} (s) / I^{-} = + 0.54 V$
${Cu}^{2 +} / Cu = + 0 . 34 V$
${Ag}^{+} / Ag = 0 . 80 V$

1. Fe³⁺
2. I₂(s)
3. Cu²⁺
4. Ag⁺

Hint: High reduction potential value strongest is the oxidisng agent

The given values are as follows:

E °

values of

{Fe}^{3 +} / {Fe}^{2 +} = + 0.77 V

I_{2} (s) / I^{-} = + 0.54 V

{Cu}^{2 +} / Cu = + 0.34 V

{Ag}^{+} / Ag = + 0.80 V

Since,

E °

of the redox couple

{Ag}^{+} / Ag

is the most positive, i.e., 0.80 V, therefore Ag⁺ is the strongest oxidising agent.