7.62 A 0.02M solution of pyridinium hydrochloride has pH = 3.44. Calculate the ionization constant of pyridine.

pH = 3.44
We know that,
pH = -log H+
H+=3.63×10-4Then, Kh=3.63×10-420.02concentration=0.02 MKh=6.6×10-6Now, Kh=KWKaKa=KwKh=10-146.6×10-6        =1.51×10-9