7.58 The solubility of Sr(OH)2 at 298 K is 19.23 g/L of solution. Calculate the concentrations of strontium and hydroxyl ions and the pH of the solution.

Solubility of Sr(OH)2 = 19.23 g/L

Then, the concentration of Sr(OH)2

=19.23121.63M=0.1581 MSrOH2aqSr2+aq+2OH-aqSr2+=0.1581 MOH-=2×0.1581 M=0.3126 MNow,Kw=OH-H+10-140.3126=H+H+=3.2×10-14pH=1.495 ; 13.50