7.6 For the following equilibrium, Kc= 6.3 × 1014 at 1000 K

NO (g) + O3 (g)  NO2 (g) + O2 (g)

Both the forward and reverse reactions in the equilibrium are elementary bimolecular reactions. What is Kc, for the reverse reaction?

It is given that Kc for the forward reaction is 6.3×1014.
Then, Kc for the reverse reaction will be, 
K'c=1Kc=16.3×1014=1.59×0-15