Match the standard free energy of the reaction with the corresponding equilibrium constant:

A \(\Delta \mathrm{G}^{\ominus}>0\) (a) K>1
B \(\Delta \mathrm{G}^{\ominus}<0\) (b) K=1
C \(\Delta \mathrm{G}^{\ominus}=0\) (c) K=0
(d) K<1
 

Codes:

A B C
1. (d) (a) (b)
2. (a) (b) (c)
3. (b) (d) (c)
4. (d) (a) (c)
HintG=-RT ln K

Explanation
As we know that, G=-RT ln K 
A. If G>0 i.e., G° is positive, then ln K is negative i.e., K<1
B. If G<0, i.e., G° is negative then ln K is positive i.e., K>1
C. If G=0, ln K=0, i.e., K=1.