34. The solubility product of $\mathrm{Al}{\left(\mathrm{OH}\right)}_{3}$ is $2.7×{10}^{-11}$. Calculate its solubility in g L-1 and also find out pH of this solution. (Atomic mass of Al=27 u)

Let S be the solubility of $\mathrm{Al}{\left(\mathrm{OH}\right)}_{3}$
$\underset{1-\mathrm{s}}{\underset{1}{\mathrm{Al}{\left(\mathrm{OH}\right)}_{3}}}⇌\underset{\mathrm{s}}{\underset{0}{{\mathrm{Al}}^{3+}}}\left(\mathrm{aq}\right)+\underset{3\mathrm{s}}{\underset{0}{3{\mathrm{OH}}^{-}}}\left(\mathrm{aq}\right)$
Concentration of species at t=0
Concentration of various species at equilibrium
(i) Solubility of $\mathbf{Al}{\mathbf{\left(}\mathbf{OH}\mathbf{\right)}}_{\mathbf{3}}$
Molar mass of $\mathrm{Al}{\left(\mathrm{OH}\right)}_{3}$ is 78 g. Therefore,
Solubility of $\mathrm{Al}{\left(\mathrm{OH}\right)}_{3}$ in
(ii) pH of the solution