32. pH of 0.08 mol dm-3 HOCl solution is 2.85. Calculate its ionisation constant.

pH of HOCl=2.85But -pH=log [H+] -2.85=log [H+]3¯.15=log [H+][H+]=1.413×10-3For weak monobasic acid [H+]=Ka×C Ka=[H+]2C=(1.413×10-3)20.08=24.957×10-6=2.4957×10-5